X^2-64x+975=0

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Solution for X^2-64x+975=0 equation: 



X^2-64X+975=0

a = 1; b = -64; c = +975;
Δ = b2-4ac
Δ = -642-4·1·975
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$


$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-14}{2*1}=\frac{50}{2}
=25
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+14}{2*1}=\frac{78}{2}
=39
$

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